1.

Correct set of quantum number for last electron of La (57):A. `n=5,l=2,m=0,s=+(1)/(2)`B. `n=6,l=2,m=0,s=+(1)/(2)`C. `n=6,l=3,m=1,s=-(1)/(2)`D. `n=6,l=3,m=-2,s=+(1)/(2)`

Answer» `La_(37)=[Xe]_(54)6s^(2)5d^(1)`
Last electron enter in 5g so n=5
l=2
m=any value from (-2 to +2) including zero
`s=+(1)/(2)` or `-(1)/(2)`


Discussion

No Comment Found

Related InterviewSolutions