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Correct set of quantum number for last electron of Pd.A. `n=5,l=2,m=0,s=-(1)/(2)`B. n=4,l=2,m=0,s=`-(1)/(2)`C. n=4,l=0,m=0,s=`-(1)/(2)`D. n=6,l=0,m=0,s=`+(1)/(4)`

Answer» `Pd_(46)=[Kr]_(36)5s^(0)4d^(10)`
`n=4, l=2,m=0,s=-(1)/(2)`


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