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Corystal field splitting energy `(CFSE)` for the complex `[Cr(H_(2)O)_(6)]^(2+)` is when `(DeltaltP)` .A. ` 1.2Delat_(0)`B. `-0.6Delta_(0)`C. `0.6Delta_(0)`D. `1.2Delta_(0)` |
Answer» Correct Answer - b Octahedral complex `CN=6,Delta lt P` (Weak ligand no pairing high spin state) `Cr = 3d^(5) 4s^(1),Cr^(+2) = 3d^(4)` ,Structure is `(t_(2g)^(3)` e_(g)^(0))` `CFSE `=(-0.4 xx 3 + 0.6)Delta_(0)=-0.6Delta_(0)` . |
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