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`cos^(3)xe^(logsinx)` |
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Answer» माना `I=intcos^(3)xe^(logsinx)dx=int(cosx)^(3)sinx dx` `" "(because e^(logx)=x)` `=-int(cosx)^(3)(-sinx)dx` माना `cosx=t" "rArr" "-sinxdx=dt` `therefore" "I=-int t^(3)dt=-(t^(4))/(4)+C=-(cos^(4)x)/(4)+C` |
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