1.

[(cos alpha-cos beta)+i(sin alpha-sinbeta)]^n+[(cos alpha-cos beta)-i(sin alpha-sin beta)]^n=

Answer»

`2^(n+1).sin^n((alpha-beta)/(2))COS[(pi/2+(alpha+beta)/(2))]`
`2^(n-1).sin^n((alpha-beta)/(2))cos[(pi/2+(alpha+beta)/(2))]`
`2^(n+1).sin^n((alpha+beta)/(2))cos[(pi/2+(alpha-beta)/(2))]`
`2^(n-1).sin^n((alpha+beta)/(2))cos[(pi/2+(alpha-beta)/(2))]`

ANSWER :A


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