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`cos[tan^(-1)""(3)/(4)]=` |
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Answer» मान `tan^(-1)""(3)/(4)=thetaimplies tan theta =(3)/(4)` `implies cos[tan^(-1)""(3)/(4)]=cos theta =(1)/(sec theta )` `= (1)/(sqrt(1+tan^(2)theta))=(1)/(sqrt(1+(9)/(16)))` `:. cos[ tan^(-1)""(3)/(4)]=(4)/(5)` |
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