1.

`cos[tan^(-1)""(3)/(4)]=`

Answer» मान `tan^(-1)""(3)/(4)=thetaimplies tan theta =(3)/(4)`
`implies cos[tan^(-1)""(3)/(4)]=cos theta =(1)/(sec theta )`
`= (1)/(sqrt(1+tan^(2)theta))=(1)/(sqrt(1+(9)/(16)))`
`:. cos[ tan^(-1)""(3)/(4)]=(4)/(5)`


Discussion

No Comment Found