cos15 - sin 15 – InterviewSolution

1.	cos15 - sin 15
Answer» Write it as cos (45-30) - sin(45-30)Now open both the functions as\xa0= cos 45 cos 30 + sin 45 sin 30 - sin 45 cos 30 + sin 30 cos 45Putting the values as learned in class X{tex}{1\\over \\sqrt2} {\\sqrt3\\over2} +{1\\over \\sqrt2} {1\\over2} - {1\\over \\sqrt2} {\\sqrt3\\over2} +{1\\over2} {1\\over \\sqrt2} {/tex}Solving we get= {tex}1\\over\\sqrt2{/tex}Answer.\xa0\xa0\xa0

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