1.

(cosalpha+isinalpha)^(5)/((sinbeta+icosbeta)^(3))=

Answer»

`SIN(5alpha+3alpha)+i COS (5alpha+3beta)`
`-sin(5alpha+3beta)+icos(5alpha+3beta)`
`sin(3alpha+5 BETA)+icos(3alpha+5beta)`
`-sin(3alpha+5beta)+icos(3alpha+5beta)`

Answer :B


Discussion

No Comment Found

Related InterviewSolutions