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`(cosec theta)/(cosec theta-1)+(cosec theta)/(cosec theta+1)=2sec^2theta` |
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Answer» We have `LHS= ("cosec" theta)/(("cosec" theta -1))+ ("cosec" theta)/(("cosec" theta +1)) ` ` = ("cosec" theta ("cosec" theta +1)+ "cosec" theta("cosec" theta -1))/(("cosec"^(2)theta -1)) ` ` = (2 "cosec"^(2)theta)/((1+ cot^(2)theta -1)) " " [ because "cosec"^(2)theta=1+cot^(2)theta] ` `= (2"cosec"^(2)theta)/(cot^(2)theta)=2 "cosec"^(2)theta tan^(2)theta ` `= 2 xx (1)/(sin^(2)theta) xx (sin^(2)theta)/(cos^(2)theta)=(2)/(cos^(2)theta) = 2 sec^(2) theta = RHS. ` |
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