| 1. |
cost ofPLE 22 Two cross roads, each of widthof a rectangular park of length 70 m ands roads, each of width 5 m, run at right angles through thelar park of length 70 m and breadth 45 m and parallel to:sides. Find the area of the roads. Also find the cost of constructiroads at the rate of 105 per m².the cost of constructing the |
|
Answer» LetABCDbe the rectangular park thenEFGHandIJKLthe two rectangular roads with width 5 m.Length of the rectangular parkAD= 70 cm Breadth of the rectangular parkCD= 45 m∴ Area of the rectangular park = Length x Breadth = 70 m x 45 m = 3150 m2Area of the roadEFGH= 70 m x 5 m = 350 m2Area of the roadJKIL= 45 m x 5 m = 225 m2Clearly area ofMNOPis common to the two roads.Thus, Area ofMNOP= 5 m x 5 m = 25 m2Hence,Area of the roads = Area (EFGH) + Area (JKIL) − Area (MNOP) = (350 + 225 ) m2− 25 m2= 550 m2Again, it is given that the cost of constructing the roads = Rs. 105 per m2Therefore,Cost of constructing 550 m2area of the roads = Rs. (105 × 550) = Rs. 57750. |
|