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| 1. |
Costruct a triangle ABC, in which angle B =60 degree ,angle = 45 degree and AB+BC+CA =10 cm |
| Answer» Steps of Construction:1.Draw a line segment PQ = 11 cm.( = AB + BC + CA).2.At P construct an angle of 60° and at Q, an angle of 45°.3.Bisect these angles. Let the bisectors of these angles intersect at a point A.4.Draw perpendicular bisectors DE of AP to intersect PQ at B and FG of AQ to intersect PQ at C.5.Join AB and AC (see Fig. 11.9). Then, ABC is the required triangle. | |