\(cot (tan^{-1}x+cot^{-1}x)=?\) A. 1B. \(\frac{1}{2}\)C. 0D. none of – InterviewSolution

1.

\(cot (tan^{-1}x+cot^{-1}x)=?\) A. 1B. \(\frac{1}{2}\)C. 0D. none of these

Answer»

Correct Answer is (C) 0

Let , x = \(cot (tan^{-1}x+cot^{-1}x)\)

⇒ x =\(cot(\frac{\pi}{2})\)

\((\because tan^{-1}x+cot^{-1}x=\frac{\pi}{2})\)

⇒ x= 0

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