`Cr_(2)O_(7)^(2-) + 14H^(+) to I_(2) + 2Cr^(3+) + 7H_(2)O` Which ions are not in balanced position in above reaction?A. `H^(+)` and `H_(2)O`B. `Cr_(2)O_(7)^(2-)` and `Cr^(3+)`C. `I^(-)` and `I_(2)`D. All are balanced

`Cr_(2)O_(7)^(2-) + 14H^(+) to I_(2) + 2Cr^(3+) + 7H_(2)O` Which ions

1.	`Cr_(2)O_(7)^(2-) + 14H^(+) to I_(2) + 2Cr^(3+) + 7H_(2)O` Which ions are not in balanced position in above reaction?A. `H^(+)` and `H_(2)O`B. `Cr_(2)O_(7)^(2-)` and `Cr^(3+)`C. `I^(-)` and `I_(2)`D. All are balanced
Answer» Correct Answer - D Since charge is not balanced for both the sides, on solving we get: `14H^(+) + Cr_(2)O_(7)^(2-) + 6I^(-) to 3I_(2) + 2Cr_(2)^(3+) + 7H_(2)O` Now, charge on LHS = charge on RHS Hence, `I^(-)` and `I_(2)` are not balanced in the given equation.

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