`[Cr(H_2 O)_6]Cl_3` (at no. of Cr = 24) has a magnetic moment of `3.83 B.M`. The correct distribution of `3d` electrons the chromium of the complex.A. (a) `3dxy^1`, `3dyz^1`, `3dz^2`B. (b) `3d^1xy`, `3d^1yz`, `3d^1zx`C. (c) `3d_((x^2-y^2)^1), 3d^1z^2, 3d^1xz`D. (d) `3dxy^1`, `3d^1x^2-y^2`, `3d^1y^2`

`[Cr(H_2 O)_6]Cl_3` (at no. of Cr = 24) has a magnetic moment of `3.83

1.	`[Cr(H_2 O)_6]Cl_3` (at no. of Cr = 24) has a magnetic moment of `3.83 B.M`. The correct distribution of `3d` electrons the chromium of the complex.A. (a) `3dxy^1`, `3dyz^1`, `3dz^2`B. (b) `3d^1xy`, `3d^1yz`, `3d^1zx`C. (c) `3d_((x^2-y^2)^1), 3d^1z^2, 3d^1xz`D. (d) `3dxy^1`, `3d^1x^2-y^2`, `3d^1y^2`
Answer» Correct Answer - B `3.83=sqrt(n(n+2))` so, `n=3` So, these are three unpaired `e^(-)s`. Based on crystal field splitting the orbital of `t_(29)` set have one `e^(-)` each.

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