InterviewSolution
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InterviewSolution
| 1. |
CRAng N, ( 1 + sec 20째 + cot 70째) ( 1-cosec 20째 + tan 70째) =2 |
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Answer» Sec 20= 1/cos 20=1/sin 70cot 70= cos 70/sin 70cosec 20= 1/sin 20= 1/cos 70 (1+sec 20 + cot 70)=1+1/sin 70+ cos 70/sin 70°taking LCM(sin 70+1 + cos 70)/sin 70 একভাবে(1-cosec 20+ tan 70)= (cos 70-1+ sin 70)/sin 70multiple both উভয় বৃদ্ধি (sin70 cos70- sin 70+sin^2 70+ cos 70-1+sin70+cos^2 70- cos 70+ sin70 cos 70)/ sin70 cos70 (2sin 70 cos 70)/ sin70 cos 70ans=2 thank s |
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