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Critical density of a gas having molecular mass `39 g mol^(-1)` is `0.1 g cm^(-3)`. Its critical volume in `L mol^(-1)` isA. `0.390`B. `3.90`C. `0.039`D. `39.0` |
Answer» Correct Answer - A Critical density `= 0.1 g cm^(-3) = 100 gL^(-1)` Critical volume `= ("Molecular mass")/("Critical density")` `= ((39 mol^(-1)))/(100 gL^(-1)) = 0.39 L mol^(-1)` |
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