

InterviewSolution
Saved Bookmarks
1. |
Crude calcium carbide is made in an electric furance by the following reactions: `CaO+3CtoCaC_2+CO`. The product contains `85%` of `CaC_2` and `15%` unreacted CaO. (a). How much CaO is to be added to the fur |
Answer» (a). `CaO+3CtoCaC_2+CO` All the CaO is not used up. Calculate how much CaO is required for 85 g of `CaC_2`. That much CaO plus 15 g excess should be taken. 15 g remains as it is. `64 g of CaC_2-=56g of CaO` `therefore85g of CaC_2-=56g of CaC` `therefore85g of CaC_2-=56xx(85)/(64)=74.374 g of CaO` Total `CaO-=74.347+15=89.374g` For each 85 g of pure `CaC_2` and 100 g of impure `CaC_2`. 85 kg pure `CaC_2=89.374kg of CaO` `1000kg pure CaCl_2=(89.374xx1000)/(85)` `=1051.46kg of CaO` (b). `100 kg` crude `CaC_2=89.374kg CaO` `therefore1000kg` crude `CaC_2=893.74kg CaO` |
|