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`K_(2)Cr_(2)O_(7)` is obtained in the following steps: `2FeCrO_(4)+2Na_(2)CO_(3)+OtoFe_(2)O_(3)+2Na_(2)CrO_(4)+2CO_(2)` `2Na_(2)CrO_(4)+H_(2)SO_(4)toNa_(2)Cr_(2)O_(7)+H_(2)O+Na_(2)SO_(4)` `Na_(2)Cr_(2)O_(7)+2KCltoK_(2)Cr_(2)+2NaCl` To get 0.25 " mol of "`K_(2)Cr_(2)O_(7)`, " mol of "`50%` pure `FeCrO_(4)` required.A. 1 molB. 0.50 molC. 0.25 molD. 0.125 mol |
Answer» Correct Answer - A 1 mol `K_(2)Cr_(2)O_(7)` is obtained from 2 " mol of "`FeCrO_(4)` 0.25 mol `K_(2)Cr_(2)O_(7)` is obtained from `-0.50 " mol of "FeCrO_(4) (100%` pure) `=1.00 mol (if 50%` pure) |
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