1.

CsBr crystallizes in a body centredcubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 and that of Br = 80 amu and Avogadro's number being 6.02times10^(23) mol^(-1), the density of CsBr is

Answer»

`8.25g//cm^(3)`
`4.25g//cm^(3)`
`0.425g//cm^(3)`
`42.5g//cm^(3)`

Solution :`d=(ZtimesM)/(a^(3)timesN_(A)times10^(-30))`
=`(1times(133+80))/((436.61)^(3)times(6.02times20^(23))times10^(-30))`
`4.25 G //cm^(3)`
(CSBR CONTAINS, one formula unit per unit CELL)


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