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`CsBr` has `bcc` structure with edge length of `43 pm`. The shortest interionic distance between cation and anion isA. `37.2`B. `18.6`C. `74.4`D. `43`

Answer» Correct Answer - A
Body diagonal `= sqrt(3)a`
Distance between `Cs^(o+)` and `Br^(ɵ)` is
`("Body diagonal")/(2) = (sqrt(3)a)/(2) = (sqrt(3) xx 43)/(2) = 3.724`


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