1.

`CsBr` has bcc stucture with edge length `4.3` pm .The shortest interionic distance in between Cs and Br isA. 1.86 pmB. 7.44 pmC. 4.3 pmD. 3.72 pm

Answer» Correct Answer - D
`CI^(-)` is pressent at conurs while `Cs^(+)` is present at Body centre, so minimum interatomic distance `=(sqrt(3a))/(2)=3.72"pm"`


Discussion

No Comment Found

Related InterviewSolutions