CsCl has bcc arrangement and its unit cell edge length is 400 pm. Calculate the interionic distance in CsCl

CsCl has bcc arrangement and its unit cell edge length is 400 pm. Calc

1.	CsCl has bcc arrangement and its unit cell edge length is 400 pm. Calculate the interionic distance in CsCl
Answer» Solution :where BLACK circle is `Cs^+` ion and coloured circles are `CL^-` ions. The aim is to FIND half of the body diagonal AE. If the edge of the UNIT cell is 'a', then `CE=sqrt(a^2+a^2)=sqrt2a` `therefore AE=sqrt((sqrt2a)^2+a^2)=sqrt3a=sqrt3xx400` `therefore` Interionic distance `=1/2AE=sqrt3xx200=346.4` pm