1.

`CsCl` has cubic structure. Its density is `3.99 g cm^(-3)`. What is the distance between `Cs^(o+)` and `Cl^(Θ)` ions? (Atomic mass of `Cs = 133`)

Answer» `CsCl` has `bc c` structure , so `Z_(eff) = 1`
`rho = (Z_(eff) xx Mw)/(rho^(3) xx 10^(-30) xx N_(A))` or `a^(3) = (Z_(eff) xx Mw)/(a^(3) xx 10^(-30) xx N_(A))`
`= (1 xx (133 + 35.5))/(3.99 xx 10^(-30) xx 6.02 xx 10^(23))`
`= 70.15 xx 10^(6)`
`a = (70.15)^(1//3) xx 10^(2)`
`= 4.12 xx 10^(2) "pm" = 412` pm
Interionic distance `= (sqrt3a)/(2)`
`= (1.732)/(2) xx 412`
`=356.8`


Discussion

No Comment Found

Related InterviewSolutions