1.

`Cu^(2+)+2e^(-) rarr Cu.` On increasing `[Cu^(2+)]`, electrode potentialA. IncreasesB. DecreasesC. No changeD. First increases, then decreases

Answer» Correct Answer - a
`Cu^(2+)(aq)+2e^(-)rarrCu(s)` ltbr. `E_(Cu^(2+)|Cu)=E^(c-)._(Cu^(2+)|Cu)-(0.059)/(2)log .(1)/([Cu^(2+)])`
`=E^(c-)._(Cu^(2+)|Cu)+(0.059)/(2)log.[Cu^(2+)]`
If `[Cu^(2+)]` increases, `E_(Cu^(2+)|Cu)` also increases.


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