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Cu_(2)S and M_(2)S are isomorphous. Percent weight of sulphur in Cu_(2)S is 20.14 and in M_(2)S is 12.9. if the atomic mass of Cu is 63.5, Calculate that of the other metal,M. |
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Answer» SOLUTION :`Cu_(2)S` contain 20.14% S and 79.86% Cu Weight of Cu that combines with 1 g of S `=(79.86)/(20.14)=3.965g` `M_(2)S` contains 12.9% S and 87.1% M Weight of M that combines with 1G of S =`(87.1)/(12.9)=6.765g` From law of isomorphism , (since VALENCY of two metals is same ) ` ("atomic mass of M ")/("atomic mass of Cu")=("Weight of M")/("weight of Cu")` Atomic mass of M `=(6.752)/(3.965)xx63.5=108` |
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