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Cu metal crystallies in face centred cubic lattic with cell edge, a =361.6pm. What is the density of Cu crystal ? (Atomic mass of copper =63.5 amu, `N_(A)=6.023xx10^(23)`) |
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Answer» We know `Z=(a^(3)xxrhoxxN_(A))/(M)` `:. Rho=(ZM)/(a^(3)N_(A))` Z=4 for fcc unit cell , `M =63.5 g mol^(-1)` `a= 361.6xx10^(-10) cm, N_(A)=6.023xx10^(23)` Putting these values in (i), we get `rho=(4xx63.5)/((36.6xx10^(-10))^(3)xx6.023xx10^(23))=8.94 g cm ^(-3)` |
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