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`[Cu(NH_(3))_(4)]^(2+)` is a square planar complex.The number of unpaired electrons and hybrid state of copper are respectivelyA. 4, `dsp^(2)`B. 1, `sp^(2)`C. 1, `dsp^(2)`D. 4s, `sp^(3)` |
Answer» Correct Answer - C `[Cu(NH_(3))_(4)]^(2+)` is square planar with one unpaired electron and `dsp^(2)`-hybridization of Cu. |
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