`Cu(s)|Cu^(+2)(aq,10^(-3))||Ag^(+)(10^(-5)M)|Ag(s)` if `E_(Cu^(+2)//Cu=0.34V` ltBrgt `E_(Ag^(+)//Ag=+0.80V` `E_("cell")` will be :-A. `0.46 V`B. `0.46-(RT)/(2F)ln 10^(7)`C. `0.46+(RT)/(2F) ln 10^(7)`D. `0.46+(RT)/(2F)ln 10^(2)`

`Cu(s)|Cu^(+2)(aq,10^(-3))||Ag^(+)(10^(-5)M)|Ag(s)` if `E_(Cu^(+2)//Cu

1.	`Cu(s)\|Cu^(+2)(aq,10^(-3))\|\|Ag^(+)(10^(-5)M)\|Ag(s)` if `E_(Cu^(+2)//Cu=0.34V` ltBrgt `E_(Ag^(+)//Ag=+0.80V` `E_("cell")` will be :-A. `0.46 V`B. `0.46-(RT)/(2F)ln 10^(7)`C. `0.46+(RT)/(2F) ln 10^(7)`D. `0.46+(RT)/(2F)ln 10^(2)`
Answer» Correct Answer - B `E_("cell")=0.85-0.34-(RT)/(2F)ln.((10^(-3)))/((10^(-5))^(2))` `=0.46-(RT)/(2F)ln10^(7)`

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`Cu(s)|Cu^(+2)(aq,10^(-3))||Ag^(+)(10^(-5)M)|Ag(s)` if `E_(Cu^(+2)//Cu=0.34V` ltBrgt `E_(Ag^(+)//Ag=+0.80V` `E_("cell")` will be :-A. `0.46 V`B. `0.46-(RT)/(2F)ln 10^(7)`C. `0.46+(RT)/(2F) ln 10^(7)`D. `0.46+(RT)/(2F)ln 10^(2)`

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