Saved Bookmarks
| 1. |
Current density of J is flowing in a resistor of resistivity \(\rho.\) We can thus recognize \(J^2\rho\) as the |
|
Answer» The answer is (3) \(J^2\rho=(\frac{I}{A})^2\times\frac{RA}{L}\) \(=\frac{I^2}{AL}.R\) = Heat generated / unit volume |
|