1.

Current density of J is flowing in a resistor of resistivity \(\rho.\) We can thus recognize \(J^2\rho\) as the

Answer»

The answer is (3)

\(J^2\rho=(\frac{I}{A})^2\times\frac{RA}{L}\)

\(=\frac{I^2}{AL}.R\)

= Heat generated / unit volume



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