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Current `i` is carried in a wire of length `L`. If the wire is turned into a circular coil, the maximum magnitude of torque in a given magnetic field `B` will beA. `(LiB^(2))/(2)`B. `(Li^(2)B)/(2)`C. `(L^(2)iB)/(4pi)`D. `(Li^(2)B)/(4pi)` |
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Answer» Correct Answer - C `tau_(max)=NiAB=1xxixx(pir^(2))xxB` `(2pir=L,impliesr=(L)/(2pi))tau_(max)=pii((L)/(2pi))^(2)B=(L^(2)iB)/(4pi)` |
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