Current I si following along the path `ABCD`, along the four edges of the cube (figure-a) creates a magnetic field in the centre at the center of the cube current I flowing along the path of the six edges `ABCDHEA` . A. `sqrt((3)/(2)) B_(0)` Towards corner `G` .B. `sqrt3 B_(0)` Towards corner `E`C. `sqrt((3)/(2)) B_(0)` Towards conrner `H` .D. `sqrt3 B_(0)` Towards corner `F` .

Current I si following along the path `ABCD`, along the four edges of

1.	Current I si following along the path `ABCD`, along the four edges of the cube (figure-a) creates a magnetic field in the centre at the center of the cube current I flowing along the path of the six edges `ABCDHEA` . A. `sqrt((3)/(2)) B_(0)` Towards corner `G` .B. `sqrt3 B_(0)` Towards corner `E`C. `sqrt((3)/(2)) B_(0)` Towards conrner `H` .D. `sqrt3 B_(0)` Towards corner `F` .
Answer» Correct Answer - D Each edge share current for two loops so cur rent for one loop is `(1)/(2)` and its field at centre of loop is `(B_(0))/(2)` There are sin loops `oversetrarr(B) =((B_(0))/(2) + (B_(0))/(2))hatk` `oversetrarrB = B_(0) hati + B_(0) hatj +B_(0hat)hatk` `B =sqrt3 B_(0)` towards `F` .

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