1.

Current supplied by the cell in the adjoining figure is A. 1.5 AB. `1 A`C. `0.1A`D. `0.5A`

Answer» Correct Answer - C
`I=(E)/(R+r)`
Where R is total external resistance `= 20 Omega`.
`:.R=(2)/(20+0)=(1)/(10)=0.1A`


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