`CuSO_(4).5H_(2)O` is blue in colour while `CuSO_(4)` is colourless. W

1.	`CuSO_(4).5H_(2)O` is blue in colour while `CuSO_(4)` is colourless. Why ?
Answer» In `CuCO_(4). 5H_(2)O` water acts as ligand and causes crystal field splitting. Hence, d-d transition is possible thus `CuSO_(4). 5H_(2)O` is coloured. In the anhydrous `CuSO_(4)` due to the absence of water (ligand), crystal field splitting is not possible and hence, it is colourless.

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`CuSO_(4).5H_(2)O` is blue in colour while `CuSO_(4)` is colourless. Why ?

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