1.

CuSO_(4).5H_(2)O(s)CuSO_(4).3H_(2)O(s)+2H_(2)O(s) K_(p)=0.4xx10^(-3)atm^(2) Which of following statement are correc:

Answer»

`DeltaG^(@)=-RTlnP_(H_(2)O)` where `P_(H_(2)O)="PARTIAL pressure of" H_(2)O` at equilibrium.
At vapour pressure of `H_(2)O=15.2` torr RELATIVE humidity of `CuSO_(4).5H_(2)O "is"100%`
In pressure of aqueous tension of `24` torr, `CuSO_(4).5H_(2)O` can not loss moisture.
In presence of dry atmosphere in open container `CuSO_(4).5H_(2)O` will completely convert into `CuSO_(4).3H_(2)O`

Solution :(A) `K_(p)=(P_(H_(2)O))^(2)`
`=0.4xx10^(-3)=4xx10^(-4)ATM^(2)`
`(P_(H_(2^O)))_(equi)=2xx10^(-2)atm`
`=2xx10^(-2)atm`
`=2xx10^(-2)xx760=15.2` torr
(B) Relative humidity`=(15.2)/(15.2)xx100=100%`(IfV.P.`=15.2` torr)
(C) When `P_(H_(2)O)gt(P_(H_(2)O))_(equi)` backward shift so at `24` torr pressure reaction shift backward.
(D) In dry atmosphere and open container reaction shift completely in forward.


Discussion

No Comment Found