1.

CuSO_(4).5H_(2)O(s)hArrCuSO_(4).3H_(2)O(s)+2H_(2)O(s) K_(P)=0.4xx10^(-3) atm^(2) Which of following sttement are correct:

Answer»

`DeltaG^(@)=-RTlnP_(H_(2)o` where `P_(H_(2)o="Partial pressure of" H_(2)O` at equilibrium.
At vapour pressure of `H_(2)O=15.2` torr relative humidity of `CuSO_(4).5H_(2)O "is" 100%`
In PRESENCE of aqueous tension of `24` torr, `CuSO_(4).5H_(2)O` can not loss molisture.
In presence of dry atmosphere in open container `CuSO_(4).5H_(2)O` will completely convert into `CuSO_(4).3H_(2)O`

SOLUTION :(A) `K_(P)=P_(H_(2)O)^(2)`
`=0.4xx10^(-3)=4xx10^(-4) atm^(2)`
`(P_(H_(2)o)_(equi)=2xx10^(-2)` atm
`=2xx10^(-2)` atm
`=2xx10^(-2)xx760=15.2` torr
(B) Relative humidity`=(15.2)/(15.2)xx100=100%` (If `V.P.=15.2` torr)
(C) When `P_(H_(2)O)gt(P_(H_(2)O)_(equi) backward shift so at `24` torr pressure reaction shift backward.
(D) In dry atmosphere and open container reaction shift completely in forward.


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