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1. |
`CuSO_(4)` dissolves in `NH_(3)` due to formation ofA. `Cu(OH)_(2)`B. `[Cu(NH_(3))_(4)]SO_(4)`C. `[Cu(NH_(3))_(4)(OH)_(2)]`D. CuO. |
Answer» Correct Answer - B `CuSO_(4)+4NH_(3) rarr [Cu(NH_(3))_(4)]SO_(4)` |
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