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cylinder is 1.45 m and its radius is 30 cm. Find thesurface area of the bird-bath. (Take 7 )ation : Let h be height of the cylinder, and r themon radius of the cylinder and hemisphere. Then,otal surface area of the bird-bath CSA of cylinder+ CSA of hemisphereFig. 13.9-2 x2 x 30(145 +30) cm2- 33000 cm2 3.3 m2EXERCISE 13.12.tated othervise, take -cubes each of volume.64 cm are joined end to end. Find the surface area of tsulting cuboid.vessel is in the form of a hollow hemisphere mounted by a hollow cylinder.

Answer»

1)Given, volume of each cube is 64 cm³⇒s³=64⇒s=∛64⇒s=4 cm.When two cubes are joined ,the length of the resulting cuboid(l) = side + side = 4+4 = 8 cmits breadth(b) = side = 4cmAnd its height(h) = side = 4cmTotal surface area of a cuboid = 2(lb+bh+hl)⇒TSA=2[(8)(4)+(4)(4)+(4)(8)]⇒TSA=2(32+16+32)⇒TSA = 2(80)⇒TSA = 160 cm²∴ The surface area of the resulting cuboid is 160 cm².



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