1.

Δ=∣∣∣∣13 cos θ1sin θ13 cos θ1sin θ1∣∣∣∣=R1→R1−R3Δ=∣∣∣∣03 cos θ−sin θ0sin θ13 cos θ1sin θ1∣∣∣∣

Answer» Δ=
13 cos θ1sin θ13 cos θ1sin θ1
=R1R1R3Δ=
03 cos θsin θ0sin θ13 cos θ1sin θ1


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