InterviewSolution
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Δ=∣∣∣∣13 cos θ1sin θ13 cos θ1sin θ1∣∣∣∣=R1→R1−R3Δ=∣∣∣∣03 cos θ−sin θ0sin θ13 cos θ1sin θ1∣∣∣∣ |
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Answer» Δ=∣∣ ∣∣13 cos θ1sin θ13 cos θ1sin θ1∣∣ ∣∣=R1→R1−R3Δ=∣∣ ∣∣03 cos θ−sin θ0sin θ13 cos θ1sin θ1∣∣ ∣∣ |
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