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D. A stone thrown vertically upwards with initial velocity u reaches a height 'h'before coming down. Show that thetime taken to go up is same as the timetaken to come down.​

Answer»

1st case u1=u1 v1=0 and t=t1distance is constant in both the casesv=u+at=0=u+a×t1_1...-u=-atfor 2nd case v1=u2=0v=u+atv2=at(for 2nd case)by SUBSTITUTING the values of u1 and v2 in equation v=u-at in both cases we get SPEED of both are EQUAL therefore t=d/speed (as speed and d are constant in both cases t1=t2.



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