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`d/(dx)[atan^(-1)x+blog((x-1)/(x+1))]=1/(x^4-1)=>a-2b=`A. 1B. `-1`C. 0D. 2 |
Answer» Correct Answer - B Given `(d)/(dx)[ a tan^(-1)x+b log((x-1)/(x+1))]=(1)/(x^(4)+1)` On intergrating both sides, we get `a tan^(-1)x+b log((x-1)/(x+1))=(1)/(2)int[(1)/(x^(2)-1)-(1)/(x^(2)+1)]dx` `rArr" " a tan^(-1)x+b log((x-1)/(x+1))=(1)/(4)log((x-1)/(x+1))-(1)/(2)tan^(-1)x` `rArr" "A=-(1)/(2), b=(1)/(4)` `therefore" "a-2b=-(1)/(2)-2((1)/(4))=-1` |
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