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ΔABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm. The height AD from A to BC, is 6 cm. Find the area of Δ ABC. What will be the height from C to AB i.e., CE? |
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Answer» In Δ ABC, AD = 6 cm and BC = 9 cm Area of triangle = 1/2 x base x height = 1/2 x BC x AD = 1/2 x 9 x 6 = 27 cm2 Again, Area of triangle = 1/2 x base x height =1/2 x AB x CE ⇒ 27 = 1/2 x 7.5 x CE ⇒ CE = (27 x 2) / 7.5 ⇒ CE = 7.2 cm Thus, height from C to AB i.e., CE is 7.2 cm. |
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