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ΔABC with sides a,b,c opposite to the angles A,B,C satisfies the equation log2(2cosC2cosA−B2)−log2(sin(A+B))=1, then the value of (a2+b2−4c2+2ab) is |
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Answer» ΔABC with sides a,b,c opposite to the angles A,B,C satisfies the equation log2(2cosC2cosA−B2)−log2(sin(A+B))=1, then the value of (a2+b2−4c2+2ab) is |
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