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Answer» The order of reaction is defined as the sum of the powers of concentrations In the rate law. The rate of second order reaction can be expressed as rate = k[A]2 The reaction X → Y follows second order kinetics. Therefore, the rate equation for this reaction will be: Rate =k[X]2 ________________________(1) Let [X] =amol L-1, then equation (1) can be written as: Rate=k[a]2 =ka2 If the concentration of X is increased to three times, then [X] = 3amol L-1 Now, the rate equation will be: Rate =k[3a]2 = 9(ka2) Hence, the rate of formation will increase by 9 times.

Answer»

The order of reaction is defined as the sum of the powers of concentrations In the rate law.

The rate of second order reaction can be expressed as rate = k[A]2

The reaction X → Y follows second order kinetics.

Therefore, the rate equation for this reaction will be:

Rate =k[X]2 ________________________(1)

Let [X] =amol L-1, then equation (1) can be written as:

Rate=k[a]2

=ka2

If the concentration of X is increased to three times, then [X] = 3amol L-1

Now, the rate equation will be:

Rate =k[3a]2

= 9(ka2)

Hence, the rate of formation will increase by 9 times.

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