1.

ddx[(x+1)(x2+1)(x4+1)(x8+1)]=(15xp−16xq+1)(x−1)−2 ⇒(p,q)=

Answer»

ddx[(x+1)(x2+1)(x4+1)(x8+1)]=(15xp16xq+1)(x1)2
(p,q)=




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