1.

de-Broglie proposed the dual nature of electron and put forward his wave concept.The wave length of electron in an orbit was given by lambda =h/(mv) The de-Broglie.s wavelength (lambda) of the electron subjected to an accelerating potential of V volts is given by

Answer»

`(CH)/(sqrt(2mv))`
`(h)/(sqrt(2mev))`
`(h)/(sqrt(2me))XX v`
`(MH)/(sqrt(2eV))`

SOLUTION :`lambda = h/m sqrt((m)/(2eV)) = (h)/(sqrt(2meV))`


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