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Decomposition of ammonium chloride is an endothermic reaction. The equilibrium may be represented as: `NH_(4)Cl(s) hArr NH_(3)(g)+HCl(g)` A `6.250 g` sample of `NH_(4)Cl` os placed in an evaculated `4.0 L` container at `27^(@)C`. After equilibrium the total pressure inside the container is `0.820` bar and some solid remains in the container. Answer the followings The amount of solid `NH_(4)Cl` left behind in the container at equilibrium isA. `2.856`B. `28.56`C. `0.2856`D. `1.320`

Answer» Correct Answer - A
moles of gases, `n=(PV)/(RT)=(0.820xx4)/(0.083xx300)=0.132` mol
moles of `NH_(3)`= moles of `HCl=0.132/2=0.066`
moles of `NH_(4)Cl` decomposed =moles of `NH_(3)=0.066`
moles of `NH_(4)Cl` initially present `=6.250/51=0.122`
mole of `NH_(4)Cl` left `=0.122-0.066=0.056`
Mass of `NH_(4)Cl` left behind `=0.056xx51=2.856 g`


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