1.

Deduce the dimensional formula of thermal conducitvity (k).

Answer» The rate at which heat is conducted through a solid rod is
`(DeltaQ)/(Deltat) = kA((DeltaT)/(Deltax)) …..(i)`
where A is area of cross section, `DeltaT//Deltax` temperature gradient, `DeltaQ` is heat conducted in `Deltat` second , k is coefficient of thermal conducitvity.
From (i) `k= (DeltaQ)/(Deltat)xx(1)/(A) ((Deltax)/(DeltaT))`
`=(ML^2 T^(-2))/(T)xx(1)/(L^2) (L)/(K)`
`k =[MLT^(-3) k^(-1)]`
Here, K represents temp. `Delta T` in kelvin.


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