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Deduce the Van der Waals equation for real gases at (a) low presssure and (b) high pressure. |
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Answer» Solution :Van der Waals EQUATION for one mole of real gas is `(P + (a)/(V_(2))) (V-b) = RT` (a) At low PRESSURE where MOLAR volume of the gas is very high, b is neglible when compared with molar volume V. `V - b = V` `(P + (a)/(V_(2))) V = RT (or) PV + (a)/(V) = RT ` `(PV)/(RT) + (a)/(RTV) =1` `(PV)/(RT) = 1 - (a)/(RTV) (or) z = 1 - (a)/(RTV)` (b) At high pressure, `(a)/(V^(2))` can be NEGLECTED when compared with P `P + (a)/(V^(2)) = P (or) P (V-b) = RT` `PV - Pb = RT (or) (PV)/(RT) = 1 + (pb)/(RT)` |
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