Define angle of friction. The inclination theta of a rough plane is increased gradually. The ply on the plane just comes into motion when inclination theta becomes 30^(@). Find coefficient of friction. If the inclination is further increased to 45^(@) then find acceleration of the body along the plane. (g = 10 m.s^(-2))

Define angle of friction. The inclination theta of a rough plane is in

1.	Define angle of friction. The inclination theta of a rough plane is increased gradually. The ply on the plane just comes into motion when inclination theta becomes 30^(@). Find coefficient of friction. If the inclination is further increased to 45^(@) then find acceleration of the body along the plane. (g = 10 m.s^(-2))
Answer» Solution :Here, ANGLE of repose `30^(@)` `:.` Coefficient of friction, `mu= tan30^(@) = (1)/(sqrt(3))` If the angle of inclinataion is `45^(@)`, the acceleration of the BODY, `a = g(SIN45^(@)-mu.cos45^(@))= 10xx(1)/(sqrt(2))(1-mu.)` `(10)/(sqrt(2))(1-(1)/(sqrt(3)))~~2.99"m.s"^(-2)[becausemu.~~mu]`