1.

Define Bohr magneton using Bohr's first hypothesis.

Answer»

Solution :1. It is DEFINED as the magnetic moment associated with an electron due to its orbital motion in the first orbit of hydrogen atom.
2. BOHR hypothesised that the angular momentum assumes a discrete set of values namely
`l=n(h/(2pi))` where n is a natural NUMBER.
n = 1, 2, 3, ... and h is a constant which is KNOWN as Planck constant.
`h=6.625xx10^(-34)Js`
3. We know that,
`(mu_(l))_(min)=e/(2m_(e))(l)`
= `e/(2m_(e))((nh)/(2pi))`
4. Taking n = 1
`(mu_(l))_(min)=(e/(2m_(e)))h/(2pi)`
= `((1.6xx10^(-19))(6.63xx10^(-34)))/(4xx3.14xx9.11xx10^(-31))`
`(mu_(l))_(min)=9.27xx10^(-24)Am^(2)`
5. Where .min. is minimum value. Minimum value of `(mu_(l))` is known as Bohr magneton.


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